(3x+4)/(x^2-9x+20)

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Solution for (3x+4)/(x^2-9x+20) equation:


D( x )

x^2-(9*x)+20 = 0

x^2-(9*x)+20 = 0

x^2-(9*x)+20 = 0

x^2-9*x+20 = 0

x^2-9*x+20 = 0

DELTA = (-9)^2-(1*4*20)

DELTA = 1

DELTA > 0

x = (1^(1/2)+9)/(1*2) or x = (9-1^(1/2))/(1*2)

x = 5 or x = 4

x in (-oo:4) U (4:5) U (5:+oo)

(3*x+4)/(x^2-(9*x)+20) = 0

(3*x+4)/(x^2-9*x+20) = 0

x^2-9*x+20 = 0

x^2-9*x+20 = 0

DELTA = (-9)^2-(1*4*20)

DELTA = 1

DELTA > 0

x = (1^(1/2)+9)/(1*2) or x = (9-1^(1/2))/(1*2)

x = 5 or x = 4

(x-4)*(x-5) = 0

(3*x+4)/((x-4)*(x-5)) = 0

3*x+4 = 0 // - 4

3*x = -4 // : 3

x = -4/3

x = -4/3

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